log₂(256)
- Input
- x=256, base=2
- Expected output
- log₂(256) = 8
2⁸ = 256 — one byte.
binary logarithm base 2
log₂(x) = number of bits needed to represent x distinct values. log₂(1024) = 10 (2¹⁰ = 1024).
2⁸ = 256 — one byte.
20 bits for ~1 million values.
log_b(x) = y means b^y = x. It is the inverse of exponentiation. Example: log₂(8) = 3 because 2³ = 8.
ceil(log₂(1000)) = ceil(9.97) = 10 bits (2¹⁰ = 1024 > 1000).
No. It helps explain the scenario and use the tool more safely, but real decisions should consider official sources, full context and qualified guidance when needed.
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